WebJan 11, 2024 · Call its ShowDialog () method to invoke the dialog box. ShowDialog () returns an enumerated type called DialogResult. It defines the identifiers, which indicates which button was clicked. For example, … WebSep 14, 2011 · 3. When the dialog receives the WM_CLOSE message it sets a flag that causes ShowDialog to return after the WM_CLOSE and any containing messages have been fully processed. So if you are doing a Dispatcher.Invoke () onto your thread to call MainWindow.Close (), the ShowDialog () won't return until after the Dispatcher.Invoke () …
Show() vs ShowDialog() in C# Windows Forms Application
WebJun 2, 2010 · C# public class CMsgBox { private delegate void InvokeDelegate (Form parent); public void ShowDialog (Form parent) { if (parent.InvokeRequired) parent.Invoke ( new InvokeDelegate (ShowDialog)); else { // Do what you need to do, you're in the foreground thread } } } WebMay 2, 2010 · 12 Answers Sorted by: 36 Change this.Close (); To: this.Hide (); Because you can't Close Main Application window and want to application runs after it. You must hide main form or change main window to window who was still opened. In this case you must close main window after ShowDialog () was ended. touch hair color
c# - 从子窗口保存数据到父窗口? - Saving Data on Parent …
WebJun 6, 2012 · 7. That's roughly correct, albeit that it is pretty important that you call the thread's SetApartmentState () method to switch the thread to STA. Important for many UI operations, including the clipboard, drag and drop and the shell dialogs. And that you usually have a crummy Z-order problem when the form that you create on the thread is not in ... WebDec 24, 2011 · Neither one is "better" than the other; they are perfectly equivalent! However, in this particular case, both are wrong.The ShowDialog method requires you to call the Dispose method on the form. Unlike the Show and Close combination, this is not done automatically. From MSDN: When a form is displayed as a modal dialog box, clicking the … WebMar 18, 2013 · use ShowDialog () instead of Show () and store the output in the DialogResult var result = _setOutput.ShowDialog (); Share Follow answered Mar 18, 2013 at 8:58 TalentTuner 17.1k 5 37 62 Add a comment 1 You can use Invoke instead of BeginInvoke : //Dispatcher.BeginInvoke (showOutput); Dispatcher.Invoke (showOutput); … touch hair dye